I was invited by Mr. Suhaimi Ramly, the head coach of the training camps to deliver geometry lectures in the IMO 2016 training camps in January, March (pre-APMO camp) and April.
IMO 2016 Camp 2: January 12-16, 2016
Lecture Delivered: Trigonometric Tricks in Solving Geometry Problems
The basics and fundamentals are almost the same as posted on my Trigonometry page.
This lecture was given to the students who had not attended training camps in any of the previous years.
The problems with solutions included in the handouts were:
APMO 2013, Problem 1.
Let ABCABC be an acute triangle with altitudes ADAD, BEBE, and CFCF, and let OO be the center of its circumcircle. Show that the segments OAOA, OFOF, OBOB, ODOD, OCOC, OEOE dissect the triangle ABCABC into three pairs of triangles that have equal areas.
APMO 2012, Problem 4.
Let ABCABC be an acute triangle. Denote by DD the foot of the perpendicular line drawn from the point AA to the side BCBC, by MM the midpoint of BCBC, and by HH the orthocenter of ABCABC. Let EE be the point of intersection of the circumcircle ΓΓ of the triangle ABCABC and the half line MHMH, and FF be the point of intersection (other than EE) of the line EDED and the circle ΓΓ. Prove that BFCF=ABACBFCF=ABAC must hold.
APMO 2013, Problem 5.
Let ABCDABCD be a quadrilateral inscribed in a circle ωω, and let PP be a point on the extension of ACAC such that PBPB and PDPD are tangent to ωω. The tangent at CC intersects PDPD at QQ and the line ADAD at RR. Let EE be the second point of intersection between AQAQ and ωω. Prove that BB, EE, RR are collinear.
IMOSL 2011, G5.
Let ABCABC be a triangle with incenter II and circumcircle ωω. Let DD and EE be the second intersection points of ωω with the lines AIAI and BIBI, respectively. The chord DEDE meets ACAC at a point FF, and BCBC at a point GG. Let PP be the intersection point of the line through FF parallel to ADAD and the line through GG parallel to BEBE. Suppose that the tangents to ωω at AA and at BB meet at a point KK. Prove that the three lines AE,BD,AE,BD, and KPKP are either parallel or concurrent.
RIMO 2014, Day 1, Problem 2.
In a quadrilateral ABCDABCD with ∠B=∠D=90∘∠B=∠D=90∘, the extensions of AB and DC meet at E; and the extensions of AD and BC meet at F. A line through B parallel to CD intersects the circumcircle ω of the triangle ABF at G distinct from B; the line EG intersects ω at P distinct from G; and the line AP intersects CE at M. Prove that M is the midpoint of CE.
IMOSL 2007, G2.
Given an isosceles triangle ABC with AB=AC. The midpoint of side BC is denoted by M. Let X be a variable point on the shorter arc MA of the circumcircle of triangle ABM. Let T be the point in the angle domain BMA, for which ∠TMX=90∘ and TX=BX. Prove that ∠MTB−∠CTM does not depend on X.
Problem solving session conducted: Trigonometric Tricks in Solving Geometry Problems
The problem solving session was themed on the same as that given in my lecture of trigonometry, except that this was targetted to a more experience group of students.
As such, the solution to the following difficult problem was demonstrated to the students:
IMO 2014, Problem 3.
Convex quadrilateral ABCD has ∠ABC=∠CDA=90∘.
Point H is the foot of the perpendicular from A to BD.
Points S and T lie on sides AB and AD, respectively,
such that H lies inside triangle SCT and
∠CHS−∠CSB=90∘,∠THC−∠DTC=90∘.
Prove that line BD is tangent to the circumcircle of triangle TSH.
IMO 2016 Camp 3: March 4-8, 2016
Lectures Delivered: Geometry Big Guns
During that camp, Justin Lim (IMO 2014 gold medallist, currently an undergraduate at MIT) and I collectively covered a few advanced level tricks in geometry.
They are detailed below (together with the problems solvable using these theorems):
Harmonic Bundles
IMOSL 2004, G8.
Given a cyclic quadrilateral ABCD, let M be the midpoint of the side CD, and let N be a point on the circumcircle of triangle ABM. Assume that the point N is different from the point M and satisfies ANBN=AMBM. Prove that the points E, F, N are collinear, where E=AC∩BD and F=BC∩DA.
Poles and Polars + Brokard's theorem
IMO 2012, Problem 5.
Let ABC be a triangle with ∠BCA=90∘, and let D be the foot of the altitude from C. Let X be a point in the interior of the segment CD. Let K be the point on the segment AX such that BK=BC. Similarly, let L be the point on the segment BX such that AL=AC. Let M be the point of intersection of AL and BK.
Show that MK=ML.
JOM 2013, G7.
Given a triangle ABC, let l be the median corresponding to the vertex A. Let E,F be the feet of the perpendiculars from B,C to AC,AB. Reflect the points E,F across l to the points P,Q. Let AP,AQ intersect BC at X,Y. Let Γ1,Γ2 be the circumcircles of △EQY,△FPX.
Prove that A lies on the line connecting the centers of Γ1,Γ2.
APMO 2013, Problem 5.
Let ABCD be a quadrilateral inscribed in a circle ω, and let P be a point on the extension of AC such that PB and PD are tangent to ω. The tangent at C intersects PD at Q and the line AD at R. Let E be the second point of intersection between AQ and ω. Prove that B, E, R are collinear.
Homothety, Monge's theorem and Monge d'Alembert's theorem
IMOSL 2007, G8.
Point P lies on side AB of a convex quadrilateral ABCD. Let ω be the incircle of triangle CPD, and let I be its incenter. Suppose that ω is tangent to the incircles of triangles APD and BPC at points K and L, respectively. Let lines AC and BD meet at E, and let lines AK and BL meet at F. Prove that points E, I, and F are collinear.
RMM 2012, Problem 6.
Let ABC be a triangle and let I and O denote its incentre and circumcentre respectively. Let ωA be the circle through B and C which is tangent to the incircle of the triangle ABC; the circles ωB and ωC are defined similarly. The circles ωB and ωC meet at a point A′ distinct from A; the points B′ and C′ are defined similarly. Prove that the lines AA′,BB′ and CC′ are concurrent at a point on the line IO.
The following problem combines the idea of all theorems above:
IMO 2008, Problem 6.
Let ABCD be a convex quadrilateral with BA≠BC. Denote the incircles of triangles ABC and ADC by ω1 and ω2 respectively. Suppose that there exists a circle ω tangent to ray BA beyond A and to the ray BC beyond C, which is also tangent to the lines AD and CD. Prove that the common external tangents to ω1 and ω2 intersect on ω.
This was a project I did at the 2012 International Mathematics Tournament of Towns Summer Conference that I attended together with Justin.
One theorem discussed during the session was the Wolstenholme's theorem,
which could be useful in solving problems in Section 4 of the attached hyperlink, and the following:
APMO 2006, Problem 3.
Let p≥5 be a prime and let r be the number of ways of placing p checkers on a p×p checkerboard so that not all checkers are in the same row (but they may all be in the same column). Show that r is divisible by p5. Here, we assume that all the checkers are identical.
IMO 2016 Camp 4: April 8-12, 2016
Lectures Delivered: Three geometry theorems (Simson's theorem, Casey's theorem, and Sawayama Thebault's theorem)
For students who want to excel in Olympiad geometry and be able to solve the hardest contest geometry problems comfortably,
mastery of these theorems is essential.
Simson's theorem
Statement: Given a point D and a triangle ABC, the feet of perpendiculars from D to sides BC,CA,AB are collinear iff D lies on the circumcircle of triangle ABC.
Applications:
IMO 2003, Problem 4.
Let ABCD be a cyclic quadrilateral. Let P,Q,R be the feet of the perpendiculars from D to the lines BC,CA,AB respectively. Show that PQ=QR if and only if the bisectors of ∠ABC and ∠ADC are concurrent with AC.
IMO 2007, Problem 2.
Consider five points A,B,C,D and E such that ABCD is a parallelogram and BCED is a cyclic quadrilateral. Let ℓ be a line passing through A. Suppose that ℓ intersects the interior of the segment DC at F and intersects line BC at G. Suppose also that EF=EG=EC. Prove that ℓ is the bisector of angle DAB.
TOT Spring Fall 2008, Senior A-Level, Problem 7.
Each of three lines cuts chords of equal lengths in two given circles. The points of intersection of these lines form a triangle. Prove that its circumcircle passes through the midpoint of the
segment joining the centres of the circles.
Statement: Let ω1, ω2, ω3 and ω4 be four non-intersecting and mutually exclusive circles, and let tij be the length of common exterior bitangent (i.e. segment connecting AiAj s.t. Ai on ωi, Aj on ωj and AiAj tangent to both circles externally. ) Then there exists a circle tangent internally to all four circles (in the order of ω1, ω2, ω3 and ω4) if and only if:
t12t34+t23t14=t13t24.
Applications:
APMO 2006, Problem 4.
Let A,B be two distinct points on a given circle O and let P be the midpoint of the line segment AB. Let O1 be the circle tangent to the line AB at P and tangent to the circle O. Let l be the tangent line, different from the line AB, to O1 passing through A. Let C be the intersection point, different from A, of l and O. Let Q be the midpoint of the line segment BC and O2 be the circle tangent to the line BC at Q and tangent to the line segment AC. Prove that the circle O2 is tangent to the circle O.
IMO 2011, Problem 6.
Let ABC be an acute triangle with circumcircle Γ. Let ℓ be a tangent line to Γ, and let ℓa,ℓb and ℓc be the lines obtained by reflecting ℓ in the lines BC, CA and AB, respectively. Show that the circumcircle of the triangle determined by the lines ℓa,ℓb and ℓc is tangent to the circle Γ.
APMO 2014, Problem 5.
Circles ω and Ω meet at points A and B. Let M be the midpoint of the arc AB of circle ω (M lies inside Ω). A chord MP of circle ω intersects Ω at Q (Q lies inside ω). Let ℓP be the tangent line to ω at P, and let ℓQ be the tangent line to Ω at Q. Prove that the circumcircle of the triangle formed by the lines ℓP, ℓQ and AB is tangent to Ω.
Sawayama Thebault's theorem
Statement: Let I be the incentre of △ABC, D a point on line BC. If a circle is tangent to the circumcircle of triagle ABC, to segment DC at E and segment DA at F. Then E,I,F are collinear.
This is another project I did at the Summer Conference mentioned above, partnered with Justin.
The project is to solve the following general problem:
There are m cakes, each with weight 1.
We are to divide the cake into slices and distribute them to n people such that everyone gets equal total weight of cake (that is, mn).
Determine the maximum k such that each slice has weight at least k
(basically, maximize the minimum possible slice).
Notice that in the official handout this quantity k is denoted as f(m,n).
Some auxillary results I discussed in the problem solving session were:
f(m,km)=1k for all positive integers k,m.
f(km,m)=1 for all positive inetegers k,m.
f(m,n)≤m2n for all m,n such that m does not divide n.
f(m,n)≥m3n for all m,n sastisfying m≤n.
When 23≤mn≤34, equality holds.
Remarkably, Justin and I submitted a solution to finding f(31,52) that was highly commended by the committee members (during the conference).
Have fun trying before looking at the answer!
Answer: f(31,52)=89364.
Acronyms Used
IMO: International Mathematical Olympiad
IMOSL: International Mathematical Olympiad, shortlisted problems
APMO: Asian Pacific Mathematical Olympiad
TOT: International Mathematics Tournament of Towns